Optimal. Leaf size=131 \[ -\frac {b^2 e^2-6 b c d e+6 c^2 d^2}{2 e^5 (d+e x)^2}-\frac {d^2 (c d-b e)^2}{4 e^5 (d+e x)^4}+\frac {2 c (2 c d-b e)}{e^5 (d+e x)}+\frac {2 d (c d-b e) (2 c d-b e)}{3 e^5 (d+e x)^3}+\frac {c^2 \log (d+e x)}{e^5} \]
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Rubi [A] time = 0.09, antiderivative size = 131, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {698} \begin {gather*} -\frac {b^2 e^2-6 b c d e+6 c^2 d^2}{2 e^5 (d+e x)^2}-\frac {d^2 (c d-b e)^2}{4 e^5 (d+e x)^4}+\frac {2 c (2 c d-b e)}{e^5 (d+e x)}+\frac {2 d (c d-b e) (2 c d-b e)}{3 e^5 (d+e x)^3}+\frac {c^2 \log (d+e x)}{e^5} \end {gather*}
Antiderivative was successfully verified.
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Rule 698
Rubi steps
\begin {align*} \int \frac {\left (b x+c x^2\right )^2}{(d+e x)^5} \, dx &=\int \left (\frac {d^2 (c d-b e)^2}{e^4 (d+e x)^5}+\frac {2 d (c d-b e) (-2 c d+b e)}{e^4 (d+e x)^4}+\frac {6 c^2 d^2-6 b c d e+b^2 e^2}{e^4 (d+e x)^3}-\frac {2 c (2 c d-b e)}{e^4 (d+e x)^2}+\frac {c^2}{e^4 (d+e x)}\right ) \, dx\\ &=-\frac {d^2 (c d-b e)^2}{4 e^5 (d+e x)^4}+\frac {2 d (c d-b e) (2 c d-b e)}{3 e^5 (d+e x)^3}-\frac {6 c^2 d^2-6 b c d e+b^2 e^2}{2 e^5 (d+e x)^2}+\frac {2 c (2 c d-b e)}{e^5 (d+e x)}+\frac {c^2 \log (d+e x)}{e^5}\\ \end {align*}
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Mathematica [A] time = 0.04, size = 126, normalized size = 0.96 \begin {gather*} \frac {-b^2 e^2 \left (d^2+4 d e x+6 e^2 x^2\right )-6 b c e \left (d^3+4 d^2 e x+6 d e^2 x^2+4 e^3 x^3\right )+c^2 d \left (25 d^3+88 d^2 e x+108 d e^2 x^2+48 e^3 x^3\right )+12 c^2 (d+e x)^4 \log (d+e x)}{12 e^5 (d+e x)^4} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (b x+c x^2\right )^2}{(d+e x)^5} \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [A] time = 0.41, size = 225, normalized size = 1.72 \begin {gather*} \frac {25 \, c^{2} d^{4} - 6 \, b c d^{3} e - b^{2} d^{2} e^{2} + 24 \, {\left (2 \, c^{2} d e^{3} - b c e^{4}\right )} x^{3} + 6 \, {\left (18 \, c^{2} d^{2} e^{2} - 6 \, b c d e^{3} - b^{2} e^{4}\right )} x^{2} + 4 \, {\left (22 \, c^{2} d^{3} e - 6 \, b c d^{2} e^{2} - b^{2} d e^{3}\right )} x + 12 \, {\left (c^{2} e^{4} x^{4} + 4 \, c^{2} d e^{3} x^{3} + 6 \, c^{2} d^{2} e^{2} x^{2} + 4 \, c^{2} d^{3} e x + c^{2} d^{4}\right )} \log \left (e x + d\right )}{12 \, {\left (e^{9} x^{4} + 4 \, d e^{8} x^{3} + 6 \, d^{2} e^{7} x^{2} + 4 \, d^{3} e^{6} x + d^{4} e^{5}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.17, size = 214, normalized size = 1.63 \begin {gather*} -c^{2} e^{\left (-5\right )} \log \left (\frac {{\left | x e + d \right |} e^{\left (-1\right )}}{{\left (x e + d\right )}^{2}}\right ) + \frac {1}{12} \, {\left (\frac {48 \, c^{2} d e^{15}}{x e + d} - \frac {36 \, c^{2} d^{2} e^{15}}{{\left (x e + d\right )}^{2}} + \frac {16 \, c^{2} d^{3} e^{15}}{{\left (x e + d\right )}^{3}} - \frac {3 \, c^{2} d^{4} e^{15}}{{\left (x e + d\right )}^{4}} - \frac {24 \, b c e^{16}}{x e + d} + \frac {36 \, b c d e^{16}}{{\left (x e + d\right )}^{2}} - \frac {24 \, b c d^{2} e^{16}}{{\left (x e + d\right )}^{3}} + \frac {6 \, b c d^{3} e^{16}}{{\left (x e + d\right )}^{4}} - \frac {6 \, b^{2} e^{17}}{{\left (x e + d\right )}^{2}} + \frac {8 \, b^{2} d e^{17}}{{\left (x e + d\right )}^{3}} - \frac {3 \, b^{2} d^{2} e^{17}}{{\left (x e + d\right )}^{4}}\right )} e^{\left (-20\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 197, normalized size = 1.50 \begin {gather*} -\frac {b^{2} d^{2}}{4 \left (e x +d \right )^{4} e^{3}}+\frac {b c \,d^{3}}{2 \left (e x +d \right )^{4} e^{4}}-\frac {c^{2} d^{4}}{4 \left (e x +d \right )^{4} e^{5}}+\frac {2 b^{2} d}{3 \left (e x +d \right )^{3} e^{3}}-\frac {2 b c \,d^{2}}{\left (e x +d \right )^{3} e^{4}}+\frac {4 c^{2} d^{3}}{3 \left (e x +d \right )^{3} e^{5}}-\frac {b^{2}}{2 \left (e x +d \right )^{2} e^{3}}+\frac {3 b c d}{\left (e x +d \right )^{2} e^{4}}-\frac {3 c^{2} d^{2}}{\left (e x +d \right )^{2} e^{5}}-\frac {2 b c}{\left (e x +d \right ) e^{4}}+\frac {4 c^{2} d}{\left (e x +d \right ) e^{5}}+\frac {c^{2} \ln \left (e x +d \right )}{e^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.42, size = 177, normalized size = 1.35 \begin {gather*} \frac {25 \, c^{2} d^{4} - 6 \, b c d^{3} e - b^{2} d^{2} e^{2} + 24 \, {\left (2 \, c^{2} d e^{3} - b c e^{4}\right )} x^{3} + 6 \, {\left (18 \, c^{2} d^{2} e^{2} - 6 \, b c d e^{3} - b^{2} e^{4}\right )} x^{2} + 4 \, {\left (22 \, c^{2} d^{3} e - 6 \, b c d^{2} e^{2} - b^{2} d e^{3}\right )} x}{12 \, {\left (e^{9} x^{4} + 4 \, d e^{8} x^{3} + 6 \, d^{2} e^{7} x^{2} + 4 \, d^{3} e^{6} x + d^{4} e^{5}\right )}} + \frac {c^{2} \log \left (e x + d\right )}{e^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.23, size = 167, normalized size = 1.27 \begin {gather*} \frac {c^2\,\ln \left (d+e\,x\right )}{e^5}-\frac {\frac {b^2\,d^2\,e^2+6\,b\,c\,d^3\,e-25\,c^2\,d^4}{12\,e^5}+\frac {x^2\,\left (b^2\,e^2+6\,b\,c\,d\,e-18\,c^2\,d^2\right )}{2\,e^3}+\frac {x\,\left (b^2\,d\,e^2+6\,b\,c\,d^2\,e-22\,c^2\,d^3\right )}{3\,e^4}+\frac {2\,c\,x^3\,\left (b\,e-2\,c\,d\right )}{e^2}}{d^4+4\,d^3\,e\,x+6\,d^2\,e^2\,x^2+4\,d\,e^3\,x^3+e^4\,x^4} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.88, size = 180, normalized size = 1.37 \begin {gather*} \frac {c^{2} \log {\left (d + e x \right )}}{e^{5}} + \frac {- b^{2} d^{2} e^{2} - 6 b c d^{3} e + 25 c^{2} d^{4} + x^{3} \left (- 24 b c e^{4} + 48 c^{2} d e^{3}\right ) + x^{2} \left (- 6 b^{2} e^{4} - 36 b c d e^{3} + 108 c^{2} d^{2} e^{2}\right ) + x \left (- 4 b^{2} d e^{3} - 24 b c d^{2} e^{2} + 88 c^{2} d^{3} e\right )}{12 d^{4} e^{5} + 48 d^{3} e^{6} x + 72 d^{2} e^{7} x^{2} + 48 d e^{8} x^{3} + 12 e^{9} x^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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